0=50x-16x^2+20

Solution for 0=50x-16x^2+20 equation:

0=50x-16x^2+20

We move all terms to the left:

0-(50x-16x^2+20)=0

We add all the numbers together, and all the variables

-(50x-16x^2+20)=0

We get rid of parentheses

16x^2-50x-20=0

a = 16; b = -50; c = -20;
Δ = b2-4ac
Δ = -502-4·16·(-20)
Δ = 3780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3780}=\sqrt{36*105}=\sqrt{36}*\sqrt{105}=6\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-6\sqrt{105}}{2*16}=\frac{50-6\sqrt{105}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+6\sqrt{105}}{2*16}=\frac{50+6\sqrt{105}}{32}
$